Problem
Given an integer n, return the least number of perfect square numbers that sum to n.
A perfect square is an integer that is the square of an integer; in other words, it is the product of some integer with itself. For example, 1, 4, 9, and 16 are perfect squares while 3 and 11 are not.
Algorithm
Dynamic programmi服务器托管网ng (DP).
Code
class Solution:
def numSquares(self, n: int) -> int:
dp = [0] * (n + 1)
for i in range(n+1):
dp[i] = i
for i in range(1, 101):
if i * 服务器托管网i > n: break
for j in range(1, n+1):
if j >= i * i and dp[j] > dp[j - i * i] + 1:
dp[j] = dp[j - i * i] + 1
return dp[n]
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