如何配置Zabbix告警邮件通知并基于GPT提供解决方案？

告警主机业务名称: {HOST.NAME}

主机IP:{HOST.IP}

告警等级: {EVENT.SEVERITY}

监控项目1:{ITEM.NAME1}

监控取值1:{ITEM.LASTVALUE1}

监控项目2:{ITEM.NAME2}

监控取值2:{ITEM.LASTVALUE2}

告警时间:{EVENT.DATE} {EVENT.TIME}

#!/usr/bin/python3

# -*- coding: utf-8 -*-

from email.mime.text import MIMEText

from email.header import Header

#from smtplib import SMTP_SSL

from smtplib import SMTP

import sys

import requests

import json

smtpaddr =服务器托管网 ‘smtp.qq.com’

myemail=’xxxxx@qq.com’ ##发送邮件的QQ

password=’xxx’ ##填写登陆客户端的授权码，在邮箱里生成同时需要打开POP3,IMAP服务

#f = open(‘/usr/local/zabbix/.passwd’,’r’)

#password = f.readline().strip()

####gpt_url = “https://aliyun.zaiwen.top/message”

gpt_url = “https://bak.cwjiaoyu.cn/message_local”

recvmail=sys.argv[1] ##发送邮件给谁

subject=sys.argv[2] ##发送的主题

content=sys.argv[3] ##发送的内容

content += ‘n’

try:

panduan = True #如果返回的是并发数过高 则重试

while panduan:

payload={“message”:[{“role”:”user”,”content”:”请详细列出关于以下运维问题的推荐解决方案是什么：” + str(subject)}],”mode”:”chatglm”,”key”:”null”}

headers = {

‘Content-Type’: ‘application/json’,

‘User-Agent’:’Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/114.0.5735.289 Safari/537.36′,

‘Host’:’jump.zaiwen.top’,

‘Origin’:’http://www.zaiwen.top’,

‘Referer’:’http://www.zaiwen.top/’

}

response = requests.request(“POST”, gpt_url, headers=headers, data=json.dumps(payload,ensure_ascii=False).encode(‘utf-8’))

if response.text != ‘[1302][您当前使用该API的并发数过高，请降低并发，或联系客服增加限额。]’:

panduan = False

content += response.text

#去掉空行

lines = content.split(‘n’)

lines = [line for line in lines if line.strip() != ”]

content = ‘n’.join(lines)

print(content)

msg = MIMEText(“””%s”””%(content), “plain”, “utf-8”) ##发送的内容

msg[‘Subject’] = Header(subject, ‘utf-8’).encode()

msg[‘From’] = myemail

msg[‘To’] = recvmail

print(msg)

#smtp = SMTP_SSL( smtpaddr )

smtp = SMTP(smtpaddr,”587″)

smtp.starttls() #启用安全传输模式

smtp.login(myemail, password)

smtp.sendmail(myemail, recvmail.split(‘,’), msg.as_string())

smtp.quit()

print(“success”)

except Exception as e:

print(“fail: “+str(e))