统计一个整数二进制中1的个数

int n = 0;
  int count = 0;
  int i = 0;
  scanf("%d", &n);
  while (n)
  {
    n = n & n - 1;
    count++;
  }

for (i = 0; i  32; i++)
  {
    if (1 == ((n >> i) & 1))
      count++;
  }