js sort排序 filter过滤

let arr = [8, 9, 5, 4, 1, 2, 3];
    //sort排序后不会生成新的数组，直接修改原数组
    arr.sort((a, b) => {
        //升序用 a-b
        // return a-b
        //降序用 b-a
        return b - a
    })

let heros = [{
        id: '101',
        name: '艾格特',
        power: 100000
    },
        {
            id: '102',
            name: '麦迪文',
            power: 130000
        },
        {
            id: '103',
            name: '古尔丹',
            power: 90000
        },
        {
            id: '104',
            name: '萨尔',
            power: 50000
        },
    ]
    heros.sort((a, b) => {
        //升序用 a-b
        // return a.power - b.power
        //降序用 b-a
        return b.power - a.power
    })

let arr = [8, 9, 5, 4, 1, 2, 3];
    let filterNumber = 5;
    const newArr = arr.filter((number) => {
        return number>filterNumber
    });
    console.log(newArr)

let heros= [{
        id: '101',
        name: '艾格特',
        power: 100000
    },
        {
            id: '102',
            name: '麦迪文',
            power: 130000
        },
        {
            id: '103',
            name: '古尔丹',
            power: 90000
        },
        {
            id: '104',
            name: '萨尔',
            power: 50000
        },
    ]
    let filterText = '尔';
    const newHeros = heros.filter((hero) => {
        return hero.name.indexOf(filterText) != -1
    });
    console.log(newHeros)